Optics NEET PYQs (1992–2026)

Solved Optics PYQs

3 recent questions with answers. The full set of 150 is free to practise.

1. NEET 2026HardInterference of Light – Young's DSE
   Q1

   In interference and diffraction, the light energy is redistributed. If it reduces in one region, producing a dark fringe, it increases in another region, producing a bright fringe.
   
   A. As there is no gain or loss of energy, these phenomena are consistent with the principle of conservation of energy.
   
   B. Diffraction and interference are characteristics exhibited only by light waves.
   
   Choose the correct answer from the options given below:

   • AA is true and B is also true
   • BA is false, but B is true
   • CA is true, but B is false
   • DBoth A and B are false

   Show answer & solution

   Correct answer: (C)

   In interference and diffraction there is no loss of energy, the energy
   
   gets redistributed. So A is true. Interference and diffraction both are
   
   exhibited in light as well as sound waves. So B is false.
2. NEET 2025MediumOptical Instruments
   Q2

   A microscope has an objective of focal length 2 cm , eyepiece of focal length 4 cm and the tube length of 40 cm . If the distance of distinct vision of eye is 25 cm , the magnification in the microscope is

   • A150
   • B250
   • C100
   • D125

   Show answer & solution

   Correct answer: (D)

   $L=40cm$ (tube length)
   $f_o=2cm$ (focal length of the objective)
   $D=25cm$ (distance of distinct vision)
   $f_e=4cm$ (focal length of the eyepiece)
   Substitute these values into the formula:
   
   $$m=\frac{40}{2}\times \frac{25}{4}$$
   
   Calculate each part:
   
   $$\begin{array}{cc}& \frac{40}{2}=20\\ & \frac{25}{4}=6.25\end{array}$$
   
   Multiply these results:
   
   $$m=20\times 6.25=125$$
   
   Thus, the magnification of the microscope is 125 .
3. NEET 2025EasyRefraction at Spherical Surfaces and Lens
   Q3

   In a certain camera, a combination of four similar thin convex lenses are arranged axially in contact. Then the power of the combination and the total magnification in comparison to the power ( $p$ ) and magnification ( $m$ ) for each lens will be, respectively

   • A$4p$ and $m^4$
   • B$p^4$ and $m^4$
   • C$4p$ and $4m$
   • D$p^4$ and $4m$

   Show answer & solution

   Correct answer: (A)

   Effective Power: When lenses are in contact, their powers add up. Therefore, the effective power $p_{\text{eff }}$ of the combination is the sum of the powers of each individual lens:
   
   $$p_{eff}=p_1+p_2+p_3+p_4=4p$$
   
   Total Magnification: The total magnification $m_{\text{eff }}$ is the product of the magnifications of each lens in the series:
   
   $$m_{eff}=m_1\times m_2\times m_3\times m_4=m^4$$
   
   Thus, for a combination of four identical lenses, the effective power is four times the power of a single lens, and the effective magnification is the fourth power of the magnification of a single lens.

Topic-wise question count

Where NEET has asked from Optics, most frequent first.

• Refraction at Spherical Surfaces and Lens35
• Interference of Light – Young’s Double Slit Experiment20
• Total Internal Reflection20
• Optical Instruments18
• Prism16
• Refraction of Light from plane surface13
• Diffraction – Single Slit Diffraction10
• Polarisation of Light8
• Plane and Spherical Mirrors6
• Interference of Light – Young's DSE3
• Huygens’ Principle and Wavefronts1

Year-wise Optics questions in NEET

Number of questions from this chapter in each year's paper(s).