Current Electricity NEET PYQs (1994–2026)

Solved Current Electricity PYQs

3 recent questions with answers. The full set of 136 is free to practise.

1. NEET 2025MediumSeries and Parallel Combination of Resistors
   Q1

   A wire of resistance $R$ is cut into 8 equal pieces. From these pieces two equivalent resistances are made by adding four of these together in parallel. Then these two sets are added in series. The net effective resistance of the combination is:

   • A$\frac{R}{16}$
   • B$\frac{R}{8}$
   • C$\frac{R}{64}$
   • D$\frac{R}{32}$

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   Correct answer: (A)

   After cutting the wire into 8 equal pieces:
   Resistance of each piece:
   Each piece has a resistance $R^{\prime }=\frac{R}{8}$.
   Parallel Combination in Each Set:
   Each set consists of 4 pieces connected in parallel:
   Resistance of each set:
   
   $$R^{{}^{\prime \prime }}=\frac{R^{\prime }}{4}=\frac{R}{32}$$
   
   Connecting the Sets in Series:
   With both sets connected in series, the equivalent resistance is calculated as:
   
   $$R_{\text{eq }}=R^{{}^{\prime \prime }}+R^{{}^{\prime \prime }}=2\times \frac{R}{32}=\frac{R}{16}$$
   
   Thus, the net effective resistance of the combination is $\frac{R}{16}$.
2. NEET 2024EasyElectric Current, Drift Velocity and Mobility
   Q2

   A uniform wire of diameter $d$ carries a current of 100 mA when the mean drift velocity of electrons in the wire is $v$. For a wire of diameter d/2 of the same material to carry a current of 200 mA , the mean drift velocity of electrons in the wire is
   [NEET 2024 Re ]

   • A4v
   • B8v
   • Cv.
   • D2v

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   Correct answer: (B)

   current $i=nA{v}_{0}e(v_d=$ mean drift velocity $)$
   $$=n\left(\frac{\pi D^2}{4}\right)v_{d}e\therefore i\propto D^2{v}_d\frac{100}{200}=\frac{(d{)}^2}{{\left(\frac{d}{2}\right)}^2}\times \frac{v}{v}\Rightarrow v^{\prime }=2\times 2^{2}v=8v$$
3. NEET 2024MediumElectrical Power
   Q3

   Two heaters $A$ and $B$ have power rating of 1 kW and 2 kW , respectively. Those two are first connected in series and then in parallel to a fixed power source. The ratio of power outputs for these two cases is:
   [NEET 2024]

   • A1:1
   • B2:9
   • C1: 2
   • D2:3

   Show answer & solution

   Correct answer: (B)

   Power Consumed $=P=\frac{V^2}{R}$
   $$\frac{P_A}{P_B}=\frac{R_B}{R_A}{R}_A=2R_B$$For Series Combination
   $$P_s=\frac{V^2}{3R_B}$$For Parallel Combination
   $$P_P=\frac{3V^2}{2R_B}\frac{P_S}{P_p}=\frac{2}{9}$$

Topic-wise question count

Where NEET has asked from Current Electricity, most frequent first.

• Wheatstone Bridge, Meter Bridge, Potentiometer29
• Electrical Power26
• Ohm’s Law, Resistance and Resistivity23
• Series and Parallel Combination of Resistors21
• Kirchhoff’s Laws (KCL and KVL)16
• Cells, EMF, Internal Resistance and Terminal Voltage13
• Electric Current, Drift Velocity and Mobility8

Year-wise Current Electricity questions in NEET

Number of questions from this chapter in each year's paper(s).