Motion in a Straight Line NEET PYQs (1988–2026)

Solved Motion in a Straight Line PYQs

3 recent questions with answers. The full set of 63 is free to practise.

1. NEET 2026MediumKinematics Basics
   Q1

   Consider a particle moving along a straight line, whose position as a function of time is given by
   
   $s(t)=\alpha t^2-\beta t+\gamma$, where
   
   $\alpha =1{ms}^{-2}$, $\beta =6{ms}^{-1}$ and $\gamma =5m$. The
   
   average speed of the particle, in ${ms}^{-1}$ from $t=0$ to
   
   $t=6s$ is:

   • A12
   • B6
   • C3
   • D0

   Show answer & solution

   Correct answer: (C)

   $v(t)=\frac{ds}{dt}=2\alpha t-\beta =2t-6$.
   
   Particle changes direction when $v=0$
   
   $\Rightarrow t=3$ s.
   
   Distance traveled: $s(0)=5$, $s(3)=9-18+5=-4$,
   
   $s(6)=36-36+5=5$.
   
   Total distance =
   
   $$\left|s(3)-s(0)\right|+\left|s(6)-s(3)\right|=|-4-5|+\left|5-(-4)\right|=9+9=18$$
   
   m.
   
   Average speed = $\frac{18}{6}=3$ m/s.
2. NEET 2026HardMotion Under Gravity
   Q2

   When a ruler falls vertically, 5 different persons catch it with different reaction times. $(g=9.8{\text{m s}}^{-2})$
   
   A. Person A has reaction time of $0.20\text{s}$.
   
   B. Person B has reaction time of $0.22\text{s}$.
   
   C. Person C has reaction time of $0.18\text{s}$.
   
   D. Person D has reaction time of $0.19\text{s}$.
   
   E. Person E has reaction time of $0.21\text{s}$.
   
   What is the correct order of the distance travelled by the ruler for each person?

   • AB > E > A > C > D
   • BC > D > A > B > E
   • CB > E > A > D > C
   • DC > D > A > E > B

   Show answer & solution

   Correct answer: (C)

   Distance $s=\frac{1}{2}g{t}^2$. Larger reaction time gives larger
   
   distance. Descending order of reaction time:
   
   $t_B>t_E>t_A>t_D>t_C$. So distance order: B > E > A
   
   > D > C.
3. NEET 2022EasyKinematical graphs
   Q3

   The position-time ( $x-t$ ) graph for positive acceleration is :
   [NEET Re-2022]

   • ANA
   • BNA
   • CNA
   • DNA

   Show answer & solution

   Correct answer: (C)

   +ve acceleration
   
   $\frac{dv}{dt}>0$ so, velocity is increasing
   $\Rightarrow$ slop of $x-t$ graph is increasing

Topic-wise question count

Where NEET has asked from Motion in a Straight Line, most frequent first.

• Kinematics Basics24
• Motion Under Gravity18
• Uniformly Accelerated Motion12
• Kinematical graphs6
• Relative Velocity3

Year-wise Motion in a Straight Line questions in NEET

Number of questions from this chapter in each year's paper(s).