Structure of Atom NEET PYQs (1988–2026)

Solved Structure of Atom PYQs

3 recent questions with answers. The full set of 86 is free to practise.

1. NEET 2026MediumElectromagnetic Radiation
   Q1

   A bulb is rated at 150 watt, converting $8\%$ energy into light. If energy of one photon is $4.42\times 10^{-19}\text{J}$, how many photons are emitted by the bulb per second?

   • A$2.71\times 10^{19}$
   • B$4.06\times 10^{19}$
   • C$27.2\times 10^{19}$
   • D$1.35\times 10^{19}$

   Show answer & solution

   Correct answer: (A)

   Total energy per second = 150 J. Light energy = $150\times 0.08=12$
   
   J.
   
   Number of photons =
   
   $\frac{12}{4.42\times 10^{-19}}=2.715\times 10^{19}$.
2. NEET 2024ModerateQuantum Numbers
   Q2

   The quantum numbers of four electrons are given below :
   
   I. $n=4;l=2;m_l=-2;s=-\frac{1}{2}$
   II. $n=3;l=2;m_l=1;s=+\frac{1}{2}$
   III. $n=4;l=1;m_l=0;s=+\frac{1}{2}$
   IV. $n=3;l=1;m_l=-1;s=+\frac{1}{2}$
   
   The correct decreasing order of energy of these electrons is

   • AIV $>$ II $>$ III $>$ I
   • BI $>$ III $>$ II $>$ IV
   • CIII $>$ I $>$ II $>$ IV
   • DI $>$ II $>$ III $>$ IV

   Show answer & solution

   Correct answer: (B)

   (I) $n=4,I=2,m_l=-2,s=-\frac{1}{2}$; represents $4d(n+I=6)$
   (II) $n=3,I=2,m_l=1,s=+\frac{1}{2}$; represents $3d(n+I=5)$
   (III) $n=4,I=1,m_l=0,s=+\frac{1}{2}$; represents $4p(n+I=5)$
   (IV) $n=3,I=1,m_l=-1,s=+\frac{1}{2}$; represents $3p(n+I=4)$
   
   Order of energy depends on the ( $n+I$ ), greater is the ( $n+I$ ) value greater is the energy, if ( $n+I$ ) is same, then it depends on n ; if ' n ' is more, energy is more.
   
   Step-1: According to $(n+1)$
   
   Energy $=$ (I) $>$ (II) $=$ (III) $>$ (IV)
   Step-2 : If $n\uparrow$, then energy increases
   Energy $=$ (I) $>$ (III) $>$ (II) $>$ (IV)
3. NEET 2024ModerateBohr Model
   Q3

   The energy of an electron in the ground state $(n=1)$ for ${He}^{+}$ion is -xJ , then that for an electron in $n=2$ state for ${Be}^{3+}$ ion in J is

   • A-x
   • B$\frac{x}{9}$
   • C$-4x$
   • D$\frac{4}{9}x$

   Show answer & solution

   Correct answer: (A)

   $$E_n=-R_H\left(\frac{z^2}{n^2}\right)J$$For ${He}^{\ast }(n=1)$,
   $$E_n=-x=-R_H\left(\frac{2^2}{1^2}\right)=-4R_H\therefore R_H=\frac{x}{4}$$For ${Be}^{3+}(n=2)$,
   $$E_n=-R_H\left(\frac{Z^2}{n^2}\right)J=-\frac{x}{4}\times \left(\frac{4\times 4}{2\times 2}\right)=-xJ$$

Topic-wise question count

Where NEET has asked from Structure of Atom, most frequent first.

• Electronic Configuration24
• Bohr Model16
• Quantum Numbers14
• Orbitals9
• Electromagnetic Radiation7
• Uncertainty Principle6
• Atomic Spectra3
• de Broglie Wavelength3
• Atomic Structure2
• Photoelectric Effect2

Year-wise Structure of Atom questions in NEET

Number of questions from this chapter in each year's paper(s).