Haloalkanes and Haloarenes NEET PYQs (1988–2025)

Solved Haloalkanes and Haloarenes PYQs

3 recent questions with answers. The full set of 67 is free to practise.

1. NEET NAModerateStereochemistry
   Q1

   If there is no rotation of plane polarised light by a compound in a specific solvent, though to be chiral, it may mean that

   • Athe compound is certainly meso
   • Bthere is no compound in the solvent
   • Cthe compound may be a racemic mixture
   • Dthe compound is certainly a chiral.

   Show answer & solution

   Correct answer: (A)

   Solution: Meso compound does not rotate plane polarised light. Compound which contains tetrahedral atoms with four different groups but the whole molecule is achiral, is known as meso compound. It possesses a plane of symmetry and is optically inactive. One of the asymmetric carbon atoms turns the plane of polarised light to the right and other to the left and to the same extent so that the rotation due to upper half is compensated by the lower half, i.e., internally compensated, and finally there is no rotation of plane polarised light.
2. NEET 2024EasyPreparation of Haloalkanes
   Q2

   The products A and B obtained in the following reactions, respectively, are
   
   $$\begin{array}{cc}& 3ROH+{PCl}_3\to 3RCl+A\\ & ROH+{PCl}_5\to RCl+HCl+B\end{array}$$
   
   [NEET 2024]

   • A${POCl}_3$ and $H_3{PO}_3$
   • B${POCl}_3$ and $H_3{PO}_4$
   • C$H_3{PO}_4$ and ${POCl}_3$
   • D$H_3{PO}_3$ and ${POCl}_3$

   Show answer & solution

   Correct answer: (D)

   These reactions are preparation of haloalkanes from alcohols.
   $$3ROH+{PCl}_3\to 3RCl+H_3{PO}_3$$(A)
   $$ROH+{PCl}_5\to RCl+HCl+{POCl}_3$$(B)
   
   A and B are $H_3{PO}_3$ and ${POCl}_3$ respectively.
3. NEET 2022ModerateReactions of Haloarenes
   Q3

   Given below are two statements : one is labelled as Assertion (A) and the other is labelled as Reason (R).
   
   Assertion (A) :
   Chlorine is an electron withdrawing group but it is ortho, para directing in electrophilic aromatic substitution.
   
   Reason (R) :
   Inductive effect of chlorine destabilises the intermediate carbocation formed during the electrophilic substitution, however due to the more pronounced resonance effect, the halogen stabilises the carbocation at ortho and para positions.
   
   In the light of the above statements, choose the most appropriate answer from the options given below :
   [NEET Re-2022]

   • A(A) is not correct but (R) is correct.
   • BBoth (A) and (R) are correct and (R) is the correct explanation of (A).
   • CBoth (A) and (R) are correct but (R) is not the correct explanation of $(A)$.
   • D(A) is correct but (R) is not correct.

   Show answer & solution

   Correct answer: (D)

   Solution:
   
   Halogen are electron withdrawing groups due to high electronegativity. They have high electron withdrawing inductive effect. In electrophilic substitution reaction it shows both electron withdrawing inductive effect and electron donating resonance effect, but inductive effect overpowers resonance effect so, it deactivates benzene ring and directs the incoming electrophile to ortho and para positions. So, here assertion is correct and Reason is false.

Topic-wise question count

Where NEET has asked from Haloalkanes and Haloarenes, most frequent first.

• Chemical Reactions of Haloalkanes27
• Stereochemistry15
• Reactions of Haloarenes8
• Preparation of Haloarenes4
• Preparation of Haloalkanes4
• Elimination Reactions4
• Organometallic Compounds2
• Preparation of Alcohols2
• Physical Properties1

Year-wise Haloalkanes and Haloarenes questions in NEET

Number of questions from this chapter in each year's paper(s).